Answer:
The amount invested in the mutual fund that earned 5% was $1,000
The amount invested in the mutual fund that earned 3% was $1,800
Step-by-step explanation:
Let
x ----> the amount invested in the mutual fund that earned 5%
y ----> the amount invested in the mutual fund that earned 3%
we know that
[tex]x+y=2,800[/tex] ----> [tex]y=2,800-x[/tex] ----> equation A
[tex]5\%=5/100=0.05[/tex]
[tex]3\%=3/100=0.03[/tex]
[tex]0.05x+0.03y=104[/tex] ----> equation B
Solve the system by substitution
substitute equation A in equation B
[tex]0.05x+0.03(2,800-x)=104[/tex]
Solve for x
[tex]0.05x+84-0.03x=104[/tex]
[tex]0.05x-0.03x=104-84[/tex]
[tex]0.02x=20[/tex]
[tex]x=\$1,000[/tex]
Find the value of y
[tex]y=2,800-x[/tex]
[tex]y=2,800-1,000=\$1,800[/tex]
therefore
The amount invested in the mutual fund that earned 5% was $1,000 and the amount invested in the mutual fund that earned 3% was $1,800