Answer:
-87.4 kJ/mol
Explanation:
We can rewrite Arrhenius' equation as:
ln(k₂/k₁) = -Ea/R * (1/T₂ - 1/T₁)
Where k₂ and k₁ are the rates of the reaction at temperatures T₂ and T₁, Ea is the activation energy and R is the universal gas constant.
For this problem:
k₂ = 5
k₁ = 17
T₂ = 15°C = 288.16 K
T₁ = 25°C = 298.16 K
R = 8.314 J/mol·K
We put the data in the equation and solve for Ea:
ln(5/17) = -Ea/8.314 J/mol·K * (1/288.16K - 1/298.16K)
-1.224 = -Ea/8.314 J/mol·K * 1.1639x10⁻⁴K⁻¹
Ea = -87416.78 J/mol ≅ -87.4 kJ/mol