In a certain country the heights of adult men are normally distributed with a mean of 66.1 inches and a standard deviation of 2.7 inches. The​ country's military requires that men have heights between 62 inches and 73 inches. Determine what percentage of this​ country's men are eligible for the military based on height.

Respuesta :

Answer:

93.03%

Step-by-step explanation:

Population mean (μ) = 66.1 inches

Standard deviation (σ) = 2.7 inches

The z-score for a given 'X' value is:

[tex]z = \frac{X- \mu}{\sigma}[/tex]

For X = 62 inches

[tex]z = \frac{62- 66.1}{2.7}\\z=-1.5185[/tex]

A z-score of -1.5185 corresponds to the 6.44-th percentile of a normal distribution.

For X = 62 inches

[tex]z = \frac{73- 66.1}{2.7}\\z=2.5555[/tex]

A z-score of 2.5555 corresponds to the 99.47-th percentile of a normal distribution.

The total percentage of men eligible for the military is the percentage within those two values, therefore:

[tex]E = 99.47-6.44\\E=93.03 \%[/tex]

93.03%  this​ country's men are eligible for the military based on height.