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A student whirls a rubber stopper attached to a string in a horizontal circle above her head. If the radius of the stopper in circular motion is a constant 50.00 cm, and the time it takes the stopper to make one full revolution is 0.2500 seconds, what is the tangential speed of the stopper?

Respuesta :

Answer:

[tex]v = 12.57 m/s[/tex]

Explanation:

As we know that the radius of the circular motion is given as

[tex]R = 50.00 cm[/tex]

time period of the motion is given as

[tex]T = 0.2500 s[/tex]

now we know that it is moving with uniform speed

so it is given as

[tex]v = \frac{2\pi R}{T}[/tex]

now plug in all data

[tex]v = \frac{2\pi(0.50)}{0.25}[/tex]

[tex]v = 12.57 m/s[/tex]