Answer:
It depends on the relation between the heights of both pyramids
Step-by-step explanation:
We know the volume of a pyramid of base b and height h is
[tex]V=\frac{1}{3}bh[/tex]
If the volume of the pyramid A is 3 times the volume of the pyramid B, then
[tex]\frac{1}{3}b_ah_a=3*\frac{1}{3}b_bh_b=b_bh_b[/tex]
Which means
[tex]b_ah_a=3*b_bh_b[/tex]
If we knew both heights are the same, we could conclude that
[tex]b_a=3*b_b[/tex]
In which case the base of the pyramid A would be greater than the other base
But if, for example, the height of the pyramid A is 3 times the height of the other height, then
[tex]3*b_a=3*b_b=>b_a=b_b[/tex]
Both bases would be the same.
If we choose that
[tex]h_a >3*h_b[/tex]
it would mean
[tex]b_a<b_b[/tex]
In which case the base of the pyramid A would be less than the other base
So the answer entirely depends on the relation between the heights of both pyramids
