The correct reaction equation is:
[tex]3NaHCO_{3} (aq) + C_{6}H_{8}O_{7} (aq) \rightarrow 3CO_{2} (g) + 3H_{2}O (l) + Na_{3}C_{6}H_{5}O_{7} (aq)[/tex]
Answer:
b) 1 mole of water is produced for every mole of carbon dioxide produced.
Explanation: CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.
a) 22.4 L of [tex]CO_{2} [/tex] gas is produced only when [tex]\frac{22.4}{3}[/tex] L of [tex]C_{6}H_{8}O_{7}[/tex] is reacted with 22.4 L of [tex]NaHCO_{3}[/tex]. So it is wrong.
b) Since in the chemical equation the stoichiometric coefficient of [tex]CO_{2}[/tex] and [tex]H_{2}O[/tex] are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. Therefore it is correct option.
c) [tex]6.02\times 10^{23}[/tex] molecules is equal 1 mole of [tex]Na_{3}C_{6}H_{5}O_{7}[/tex] if produced then 3 moles of [tex]NaHCO_{3}[/tex] is required, which is not given in the option. So it is wrong.
d) 54 g of water or 3 moles of [tex]H_{2}O[/tex] (Molecular Weight of water is 18 g) is produced when 3 moles of [tex]NaHCO_{3}[/tex] is used but in this option only one mole of [tex]NaHCO_{3}[/tex] is given. So it is wrong.
Answer:
Connexus: A,A,A,B.
Explanation:
These are the correct answers to Chemical Calculations Lesson 2 unit 6 stoichiometry answers.
Hope this helps:)
