A large jetliner with a wingspan of 40 m flies horizontally and due north at a speed of 300 m/s in a region where the magnetic field of earth is 60 uT directed 50 degrees below the horizontal. What is the magnitude of the induced emf between the ends of the wing?

a) 250 mV
b)350 mV
c) 550 mV
d) 750 mV

Respuesta :

Answer:

Answer is C) ; 550 mv

Step-by-step explanation:

Faraday's law states: Induced EMF is equal to the rate of change of magnetic flux.

Magnetic flux = Magnetic field strength x Area = BA.

Rate of change implies we consider the variable with respect to time (in seconds)

Therefore...Induced EMF = (change in Magnetic Flux Density x Area)/change in Time.

OR EMF = BA/t

If we are doing it with a coil, the area becomes the area of one coil multiplied by the number of coils, n = πr2n

Therefore, Induced EMF = (Bπr2n)/t.

If we want to increase the amount of EMF induced, we either...

Increase the area 'swept'.

Increase the Magnetic Flux Density.

Decrease the amount of time taken.

The EMF induced is also proportional to the speed of the object going through the Magnetic Flux.

Because BA/t can be re-written as...EMF = Magnetic flux density x Width x Speed.

This is because speed = distance / time.

REMEMBER! - EMF is measured in volts, magnetic flux density is measured in teslas and area is measured in meters2, time is measured in seconds.

So you will have to convert things from mm, cm, km, minutes, etc.