Answer:
V = 4.67 m/s
Explanation:
given,
mass of the flying bird (M)= 340 g = 0.34 Kg
Speed of bird(u₁) = 6 m/s
mass of insect(m) = 13 g = 0.013 Kg
speed of insect(u₂) = 30 m/s
Speed of bird after eating the insect(V) =?
Using conservation of momentum
M u₁ + m u₂ = (M+m)V
[tex]V = \dfrac{M u_1+ m u_2}{(M+m)}[/tex]
[tex]V = \dfrac{0.34\times 6 - 0.013 \times 30}{0.34+0.013}[/tex]
[tex]V = \dfrac{1.65}{0.353}[/tex]
V = 4.67 m/s
the bird's speed immediately after swallowing V = 4.67 m/s
