Answer:
0.00119
Explanation:
F = Force = 44500 N
A = Area = [tex]0.0152\times 0.0191\ m^2[/tex]
E = Young's modulus of copper = [tex]128\times 10^{9}\ Pa[/tex]
Stress is given by
[tex]\sigma=\frac{F}{A}[/tex]
Strain is given by
[tex]\epsilon=\frac{\sigma}{E}\\\Rightarrow \eplison=\frac{\frac{F}{A}}{E}\\\Rightarrow \epsilon=\frac{\frac{44500}{0.0152\times 0.0191}}{128\times 10^{9}}\\\Rightarrow \epsilon=0.00119[/tex]
The resulting strain is 0.00119
