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Unpolarized light is passed through an optical filter that is oriented in the vertical direction. 1) If the incident intensity of the light is 90 W/m2, what is the intensity of the light that emerges from the filter? (Express your answer to two significant figures.)

Respuesta :

Answer:

45 W/m^2

Explanation:

Intensity of light, Io = 90 W/m^2

According to the law of Malus

[tex]I=I_{0}Cos^{2}\theta[/tex]

The average value of Cos^θ is half

So, I = Io/2

I = 90 /2

I = 45 W/m^2

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