Answer:
[tex]-\dfrac{1}{3}[/tex]
Step-by-step explanation:
The given function is
[tex]y=3x+1[/tex]
We need to find all real zeros of the given function.
Equate y=0, to find all real zeros of the given function.
[tex]3x+1=0[/tex]
Subtract 1 from both sides.
[tex]3x+1-1=0-1[/tex]
[tex]3x=-1[/tex]
Divide both sides by 3.
[tex]\dfrac{3x}{3}=\dfrac{-1}{3}[/tex]
[tex]x=-\dfrac{1}{3}[/tex]
Therefore, the real zero of the function is -1/3.
