The radius of Earth is about 6450 km. A 7070 N spacecraft travels away from Earth. What is the weight of the spacecraft at a height 6450 km above Earth’s surface? Answer in units of N. What is the weight 33700 km above Earth’s surface? Answer in units of N.

Respuesta :

Answer:

(a). The weight of spacecraft at height 6450 km is [tex]1.767\times10^{3}\ N[/tex].

(b). The weight of spacecraft at height 33700 km is 182.46 N.

Explanation:

Given that,

Radius of earth = 6450 km

Weight of spacecraft = 7070 N

We need to calculate the weight of the spacecraft at a height 6450 km above Earth’s surface

Using formula of weight

[tex]W_{r}=W(\dfrac{r_{e}}{r_{e}+h})^2[/tex]

Where, W = weight of spacecraft

h = height

Put the value into the formula

[tex]W_{r}=7070\times(\dfrac{6450\times10^{3}}{6450\times10^3+6450\times10^3})^2[/tex]

[tex]W_{r}=1.767\times10^{3}\ N[/tex]

(b). We need to calculate the weight of spacecraft at height 33700 km

Using formula of weight

[tex]W_{r}=7070\times(\dfrac{6450\times10^{3}}{6450\times10^3+33700\times10^3})^2[/tex]

[tex]W_{r}=182.46\ N[/tex]

Hence, (a). The weight of spacecraft at height 6450 km is [tex]1.767\times10^{3}\ N[/tex].

(b). The weight of spacecraft at height 33700 km is 182.46 N.