Answer:
Friction force is 10.025 N
Solution:
As per the question:
Mass, m = 66 kg
Now,
We know that the value of the coefficient of friction for the knee joint fluid,
[tex]\mu = 0.0155[/tex]
Now,
The friction force is given by:
[tex]f = \mu N[/tex]
N = Normal reaction force = weight = mg
[tex]f = \mu \times m\times g[/tex]
[tex]f = 0.0155\times 66.0\times 9.8 = 10.025\ N[/tex]
