Answer:
Step-by-step explanation:
A motorist drove 150 miles in the morning and 50 miles in the afternoon
His average rate in the morning was twice his average rate in the afternoon
He spent 5 hours driving
As=t*d
Cross multiply!!!
This is the equation
(750 - 150x = 100x =250x = 750 = x=3)
AS (Average speed is 50 mph
AS 25 mph
Hope it helps!
Answer:
His average rate in the morning was [tex]50\ \frac{mi}{h}[/tex]
His average rate in the afternoon was [tex]25\ \frac{mi}{h}[/tex]
Step-by-step explanation:
We need to remember the following formula:
[tex]V=\frac{d}{t}[/tex]
Where "V" is the speed, "d" is the distance and "t" is the time.
Solving for "t":
[tex]t=\frac{d}{V}[/tex]
Let be [tex]x[/tex] the average rate in the afternoon and [tex]2x[/tex] the average rate in the morning.
Since he spent 5 hours driving, we can write the following equations:
[tex]5=\frac{150}{2x}+\frac{50}{x}[/tex]
Solving for "x", we get:
[tex]5=\frac{150}{2x}+\frac{50}{x}\\\\5=\frac{75+50}{x}\\\\5x=125\\\\x=\frac{125}{5}\\\\x=25[/tex]
Therefore, his average rate in the afternoon was:
[tex]x=25\ \frac{mi}{h}[/tex]
And his average rate in the morning was:
[tex]2x=2(25)=50\ \frac{mi}{h}[/tex]
