contestada

The speed in case a is twice that of case b. The circles radius in case a is two times that of case b. How does the acceleration in case a compare to the acceleration in case b?

Respuesta :

Answer:

acceleration of a is twice the acceleration of b.

Explanation:

va = 2v

vb = v

ra = 2r

rb = r

Acceleration is given by

[tex]A=\frac{v^{2}}{r}[/tex]

So, acceleration of a is given by

[tex]A_{a}=\frac{4v^{2}}{2r}[/tex]....(1)

acceleration of b is given by

[tex]A_{b}=\frac{v^{2}}{r}[/tex].... (2)

dividing (1) by (2), we get

[tex]\frac{A_{a}}{A_{b}}=2[/tex]

Thus, acceleration of a is twice the acceleration of b.

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