Answer: No, these response does not provide strong evidence that the 34% figure is not accurate for this region.
Step-by-step explanation:
Since we have given that
p = 0.34
x= 228
n = 750
So, [tex]\hat{p}=\dfrac{x}{n}=\dfrac{228}{750}=0.304[/tex]
So, hypothesis would be
[tex]H_0:p=\hat{p}\\\\H_a:p\neq \hat{p}[/tex]
So, test statistic value would be
[tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.304-0.38}{\sqrt{\dfrac{0.38\times 0.62}{750}}}\\\\z=\dfrac{-0.076}{0.0177}\\\\z=-4.293[/tex]
At 95% confidence , z = 1.96
So, 1.96>-4.293.
So, we accept the null hypothesis.
No, these response does not provide strong evidence that the 34% figure is not accurate for this region.