Answer : The amount of heat needed is, 9405 J
Explanation :
Formula used :
[tex]Q=m\times c\times \Delta T[/tex]
or,
[tex]Q=m\times c\times (T_2-T_1)[/tex]
where,
Q = heat required = ?
m = mass of ice = 150 g
c = specific heat of water = [tex]4.18J/g^oC[/tex]
[tex]T_1[/tex] = initial temperature = [tex]-30^oC[/tex]
[tex]T_2[/tex] = final temperature = [tex]-15^oC[/tex]
Now put all the given value in the above formula, we get:
[tex]q=150g\times 4.18J/g^oC\times [(-15)-(-30)]^oC[/tex]
[tex]q=9405J[/tex]
Therefore, the amount of heat needed is, 9405 J
