Answer:
The internal resistance of the cell is, r = 2.27 Ω
Explanation:
Given data,
The voltage of the battery, v = 1.49 V
The external resistor of resistance, R = 3.2 Ω
The current through the circuit after connecting resistor, I = 0.27 A
The theoretical value of current through the circuit,
Iₓ = v / R
= 1.49 / 3.2
= 0.4585 A
But, the actual reading of the current through the circuit is,
I = 0.27 A
Therefore, the total resistance Rₓ = v / I
= 1.49 / 0.27
= 5.52 Ω
Therefore, the internal resistance of the cell,
r = Rₓ - R
= 5.52 Ω - 3.2 Ω
∴ r = 2.27 Ω
