Answer:[tex]0.5 rad/s^2[/tex]
Explanation:
Given
Moment of inertia of cylinder [tex]I=4 kg-m^2[/tex]
Angular velocity after 2 s is [tex]\omega _2=1 rad/s[/tex]
initial angular velocity [tex]\omega _1=0 rad/s[/tex]
Using
[tex]\omega _2=\omega _1+\alpha t[/tex]
where [tex]\alpha =angular\ acceleration[/tex]
[tex]1=0+\alpha \times 2[/tex]
[tex]\alpha =\frac{1}{2}=0.5 rad/s^2[/tex]
