1) Eliot and William went hiking. They went at the same speed. Eliot's hike was 8 miles, and William's hike was 12 miles. It took Eliot 40 min less than William. How long was William's hike?
2) During a certain period of time, a car can cover a distance of 120 miles, going at an average speed of 55 mph. What distance over the same period of time would cover a truck, going at an average speed of 44 mph?

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Respuesta :

frika

Answer:

1) 2 hours

2) 96 miles

Step-by-step explanation:

1) Eliot and William went hiking. They went at the same speed. Let x mph be their speed.

Elliot:

Distance = 8 miles

Speed = x mph

Time [tex]=\dfrac{8}{x}[/tex] hours

William:

Distance = 12 miles

Speed = x mph

Time [tex]=\dfrac{12}{x}[/tex] hours

It took Eliot [tex]40\ min=\dfrac{40}{60}\ hour=\dfrac{2}{3}\ hour[/tex] less than William, then

[tex]\dfrac{8}{x}+\dfrac{2}{3}=\dfrac{12}{x}\\ \\\dfrac{2}{3}=\dfrac{12}{x}-\dfrac{8}{x}\\ \\\dfrac{2}{3}=\dfrac{4}{x}\\ \\2x=3\cdot 4\ \ [\text{Cross multiply}]\\ \\2x=12\\ \\x=6\ mph[/tex]

So, William's hike was

[tex]\dfrac{12}{6}=2[/tex]

hours long.

2) Initially:

Distance = 120 miles

Speed = 55 mph

Time [tex]=\dfrac{120}{55}=2\dfrac{10}{55}=2\dfrac{2}{11}\[/tex] hours

Final:

Speed = 44 mph

Time [tex]=2\dfrac{2}{11}[/tex] hours

Distance [tex]=44\cdot 2\dfrac{2}{11}=44\cdot \dfrac{24}{11}=4\cdot 24=96\ miles[/tex]