David is riding on a flying carousel which swings him in circles of radius R=4.0R=4.0m, at a height of h=6h=6 m above the ground. The carousel rotates counterclockwise once every 5 sec.
When he is on the west side of the carousel, David's hat falls off.

Where does the hat land (relative to the point where it fell off)?

Respuesta :

Answer:

5.55935324 m

Explanation:

r = Radius = 4 m

h = Height = 6 m

Frequency is

[tex]f=\frac{1}{T}\\\Rightarrow f=\frac{1}{5}\ Hz[/tex]

Angular speed is given by

[tex]\omega=2\pi f\\\Rightarrow \omega=\frac{2}{5}\pi[/tex]

Tangential velocity of the hat is given by

[tex]v=r\omega\\\Rightarrow v=4\times\frac{2}{5}\pi\\\Rightarrow v=5.02654\ m/s[/tex]

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s²

From equation of motion

[tex]s=ut+\frac{1}{2}gt^2\\\Rightarrow 6=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{6\times 2}{9.81}}\\\Rightarrow t=1.106\ s[/tex]

Distance = Speed×Time

[tex]Distance=5.02654\times 1.106=5.55935324\ m[/tex]

The hat will land 5.55935324 m away from the point of release