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If the concentration of a saturated solution at 0∘C is 12.5 gCuSO4/100 g soln, what mass of CuSO4⋅5H2O would be obtained? [Hint: Note that the solution composition is stated in terms of CuSO4 and that the solid that crystallizes is the hydrate CuSO4⋅5H2O.]

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Answer:

Mass of CuSO4.H2O obtained: [tex]m_{total}=19.52 g[/tex]

Explanation:

The molecular weight of the salt is: [tex]M=159.5 g/mol[/tex]

In the solution: 12.5 g of CuSO4

In moles: [tex]n=\frac{12.5 g}{159.5 g/mol}=0.078 mol[/tex]

Mass of water:

5 moles of water per mol of salt: [tex]m=\frac{5mol}{1mol}*0.078mol*\frac{18g}{mol}=7.02 g[/tex]

Mass of CuSO4.H2O obtained: [tex]m_{total}=12.5 g + 7.02 g=19.52 g[/tex]

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