Respuesta :
Answer:
0.0239
Step-by-step explanation:
A publisher reports that 49% of their readers own a personal computer.
Claim : . A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.
[tex]H_0:p = 0.49\\H_a:p\neq 0.49[/tex]
A random sample of 200 found that 42% of the readers owned a personal computer.
No. of people owned a personal computer = [tex]42\% \times 200[/tex]
= [tex]\frac{42}{100} \times 200[/tex]
= [tex]84[/tex]
[tex]x = 84\\n = 200[/tex]
We will use one sample proportion test
[tex]\widehat{p}=\frac{x}{n}[/tex]
[tex]\widehat{p}=\frac{84}{200}[/tex]
[tex]\widehat{p}=0.42[/tex]
Formula of test statistic =[tex]\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
=[tex]-1.98[/tex]
Now refer the p value from the z table
p value =0.0239
Hence The p value of test statistic is 0.0239
