Answer:
Molarity of HCl = 0.19 M
Explanation:
Moles of [tex]Na_2CO_3[/tex]:-
Mass = 0.246 g
Molar mass of [tex]Na_2CO_3[/tex] = 105.988 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{0.246\ g}{105.988\ g/mol}[/tex]
[tex]Moles_{Na_2CO_3}= 0.002321\ mol[/tex]
According to the given reaction:-
[tex]Na_2CO_3+2HCl\rightarrow 2NaCl+H_2O+CO_2[/tex]
1 mole of [tex]Na_2CO_3[/tex] react with 2 moles of HCl
0.002321 mole of [tex]Na_2CO_3[/tex] react with 2*0.002321 moles of HCl
Moles of HCl = 0.004642 moles
Given that volume = 24.3 mL
Also,
[tex]1\ mL=10^{-3}\ L[/tex]
So, Volume = 24.3 / 1000 L = 0.0243 L
Considering:
[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]
[tex]Molarity=\frac{0.004642}{0.0243}[/tex]
Molarity of HCl = 0.19 M
