Answer:0.906 N/m
Explanation:
Given
time period [tex]T=0.66 s[/tex]
mass [tex]m=0.01 kg[/tex]
System can be considered as spring mass system
Time Period of spring mass system is given by
[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]
squaring
[tex]k=\frac{4\pi ^2m}{T^2}[/tex]
[tex]k=\frac{4\times \pi ^2\times 0.01}{0.66^2}[/tex]
[tex]k=0.906 N/m[/tex]
