Answer: 3.5units
Explanation:
Gravitational force existing between the two masses is directly proportional to the product of their masses and inversely proportional to the square of the distances between the masses.
Mathematically, F = GMm/r^2
G is the gravitational constant
M and m are the masses
r is the distance between the masses.
If the force of attraction between the masses is 16units, it becomes,
16 = GMm/r^2... (1)
If the mass of object 1 is doubled and distance tripled, we will have
F= G(2M)m/(3r)^2
F=2GMm/9r^2... (2)
Solving eqn 1 and 2 to get the new Force
Dividing eqn 1 by 2, we have
16/F = GMm/r^2 ÷ 2GMm/9r^2
16/F = GMm×9r^2/r^2×2GMm
16/F = 9/2(upon cancelation)
Cross multiplying we have
9F=32
F= 32/9
F= 3.5units
Answer:
Answer: F = 4 units
Explanation:
If the distance is increased by a factor of 2, then force will be decreased by a factor of 4 (22). The new force is then 1/4 of the original 16 units.
F = (16 units ) / 4 = 4 units
