The required numbers are 6 and 3
Solution: Assume the required numbers are a and b,
Given that the sum of two numbers is nine that is, [tex]a+b=9\rightarrow(1)[/tex]
One number is three more than the other that is, [tex]a=b+3\rightarrow(2)[/tex]
On substituting (2) in (1) we get,
[tex]\Rightarrow b+3+b=9\rightarrow 2b+3=9[/tex]
On grouping the similar terms we get,
[tex]\Rightarrow 2b=9-3 \rightarrow 2b=6 \rightarrow[/tex]
[tex]\Rightarrow b=\frac{6}{2}\rightarrow b=3 \rightarrow (3)[/tex]
On substituting (3) in (1) we get,
[tex]a+3=9\rightarrow a=9-3\rightarrow a=6[/tex]
Therefore, the number are 6 and 3.
