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Arrange the following molecules in order of increasing bond angles (smallest first): (A) XeF4.(B) CH4.(C) H2O.(D) BeH2. Enter four letters in order: (e.g. ABCD, DCBA, ACBD, etc.)"

Respuesta :

Answer:

ACBD

Explanation:

The bond angles of the given molecules will be:

[tex]XeF_{4}[/tex]

Square planar shape

Bond angle = 90°

[tex]CH_{4}[/tex] =

Tetrahedral

Bong angle = 109.5°

[tex]H_{2}O[/tex] =

Bent shape

Bong angle = 104.5°

[tex]BeH_{2}[/tex] =

Linear

Bong angle = 180°

Thus the order will be:

[tex]XeF_{4}[/tex] <[tex]H_{2}O[/tex]<[tex]CH_{4}[/tex]<[tex]BeH_{2}[/tex]

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