Answer:
-0.4454 Joules
Explanation:
m = Mass of block = 2 kg
h = Height of extension = 17 cm = x
g = Acceleration due to gravity = 9.81 m/s²
Potential energy of the spring
[tex]P=mgh\\\Rightarrow P=2\times 9.81\times 0.17\\\Rightarrow P=3.3354\ J[/tex]
The kinetic energy of the spring
[tex]K=\frac{1}{2}mx^2\\\Rightarrow K=\frac{1}{2}\times 200\times 0.17^2\\\Rightarrow K=2.89\ J[/tex]
In this system as the potential and kinetic energy is conserved from work energy equivalence we get
[tex]W=P-K\\\Rightarrow W=2.89-3.3354\\\Rightarrow W=-0.4454\ J[/tex]
The work done by friction is -0.4454 Joules
