Answer:[tex]\mu [/tex]=0.48
Explanation:
Given
inclination [tex]\theta =31^{\circ}[/tex]
Acceleration of object[tex]=0.99 m/s^2[/tex]
Now using FBD
[tex]mg\sin \theta -f_r=ma[/tex]
[tex]mg\sin \theta -\mu mg\cos \theta =ma[/tex]
[tex]a=g\sin \theta -\mu g\cos \theta [/tex]
[tex]0.99=5.04-\mu 8.4[/tex]
[tex]\mu 8.4=4.057[/tex]
[tex]\mu =0.48[/tex]
