The centripetal acceleration is [tex]0.63 m/s^2[/tex]
Explanation:
The centripetal acceleration for an object in circular motion is given by
[tex]a=\frac{v^2}{r}[/tex]
where
v is the linear speed
r is the radius of the circle
The body in the problem cover half of revolution in
t = 10 s
And the corresponding linear distance covered is
L = 10 m
which corresponds to half of the circumference, so
[tex]L=2\pi r[/tex]
From this equation we find the radius of the circle:
[tex]r=\frac{L}{2\pi}=\frac{10}{2\pi}=1.59 m[/tex] [m]
While the linear speed is:
[tex]v=\frac{L}{t}=\frac{10}{10}=1 m/s[/tex]
Therefore, the centripetal acceleration is
[tex]a=\frac{1^2}{1.59}=0.63 m/s^2[/tex]
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
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