3. (a) What is the maximum frictional force in the knee joint of a person who supports 66.0 kg of her mass on that knee? (b) During strenuous exercise it is possible to exert forces to the joints that are easily ten times greater than the weight being supported. What is the maximum force of friction under such conditions? The frictional forces in joints are relatively small in all circumstances except when the joints deteriorate, such as from injury or arthritis. Increased frictional forces can cause further damage and pain.

Respuesta :

Answer:

(a) 103.49 N

(b) 970.2 N

Solution:

As per the question:

Mass, m = 66 kg

Force = 10 weight = 10 mg N

where

g = acceleration due to gravity

Now,

(a) To calculate the maximum frictional force:

[tex]f = \mu N[/tex]

where

f = frictional force

[tex]\mu = 0.16[/tex] = coefficient of friction

N = mg = normal reaction

[tex]f = \mu mg = 0.16\times 66\times 9.8 = 103.49\ N[/tex]

(b) In this case, to calculate the frictional force:

[tex]f' = \mu_{k} F = \mu_{k} 10mg[/tex]

where

[tex]\mu_{k} = 0.15[/tex]

Now,

[tex]f' = 0.15\times 10\times 66\times 9.8 = 970.2\ N[/tex]