Answer:
46.218 m
Explanation:
Distance = Speed × Time
[tex]Distance=\frac{6}{3.6}\times 11=\frac{55}{3}\ m[/tex]
Distance traveled by Brooke is [tex]\frac{55}{3}\ m[/tex]
[tex]Distance=\frac{7}{3.6}\times 11=\frac{70}{3}\ m[/tex]
Distance traveled by Jamail is [tex]\frac{70}{3}\ m[/tex]
From Pythagoras theorem
[tex]s=\sqrt{20^2+\left(\frac{125}{3}\right)^2}\\\Rightarrow s=46.218\ m[/tex]
The distance between Brooke and Jamail after 11 seconds is 46.218 m
