Respuesta :
Answer:
(a) [tex]KE=16405.215 J[/tex]
(b) P = 6309.6981 W
(c) Value in above part is described as minimum because there would have been power loss in the actual system to achieve this acceleration from the state of rest.
Explanation:
Given:
mass of car, m = 1140 kg
expression of acceleration, [tex]a=1.14t-0.210t^2+0.240t^3[/tex]
where "t" is time in seconds
initial time, [tex]t_i=0 s[/tex]
final time, [tex]t_f=2.6 s[/tex]
(a)
We know,
[tex]\frac{dv}{dt} =a[/tex]
[tex]dv=a.dt[/tex]
[tex]v=\int\limits^{2.6}_0 {1.14t-0.210t^2+0.240t^3} \, dt[/tex]
[tex]v=5.3648 m.s^{-1}[/tex]
Kinetic Energy
∴[tex]KE= \frac{1}{2} m.v^2[/tex]
[tex]KE=\frac{1}{2}\times 1140\times 5.3648^2[/tex]
[tex]KE=16405.215 J[/tex]
(b)
We know,
Power
[tex]P= \frac{\Delta KE}{\Delta t}[/tex]
[tex]P=\frac{16405.215}{2.6}[/tex]
P = 6309.6981 W
(c)
Value in above part is described as minimum because there would have been power loss in the actual system to achieve this acceleration from the state of rest.
