Respuesta :
Answer:
The Distance cover by both the Runners is same = 10 miles
Step-by-step explanation:
According to question ,
The Speed of first runners (S 1) = 5 miles per hour
The speed of second runners (S 2) = 4 miles per hour
Let The Time taken by First runner (T 1 ) = T hour
But the second runner arrives half hour after the first runner ,
I.e The Time taken by Second runner (T 2) = ( T + [tex]\frac{1}{2}[/tex] )
Now from Distance = Speed × Time
Since both the runners start from same place and run along the same trail
SO ,Both the Distance cover by both are same , D 1 = D 2
i.e Speed 1 × Time 1 = Speed 2 × Time 2
5 mph × T = 4 mph × ( T + [tex]\frac{1}{2}[/tex] )
5 T = 4 T + ( 4 × [tex]\frac{1}{2}[/tex] )
Or, 5 T - 4 T = 2
∴ T = 2 hour ,
Time take by first = T1 = T = 2 hour
Time take by second = T2 = T + [tex]\frac{1}{2}[/tex] = (2 + [tex]\frac{1}{2}[/tex] )hour = [tex]\frac{5}{2}[/tex]
Now the Distance cover = Speed × Time
Distance (D1) = 5 mph × 2 hour = 10 mile
And Distance (D2) = 4 mph × [tex]\frac{5}{2}[/tex] = 10 miles
Hence, As The Distance cover by both the Runners is same = 10 miles Answer
