Answer
given,
work = 5 J
spring stretch form 30 cm to 39 cm
[tex]W = \dfrac{1}{2}kx^2[/tex]
x = 0.39 - 0.30 = 0.09 m
[tex]5 = \dfrac{1}{2}k\times 0.09^2[/tex]
[tex]k = \dfrac{5\times 2}{0.09^2}[/tex]
k = 1234.568 N/m
a) work when spring is stretched from 32 cm to 34 cm
x₂= 0.34 -0.30 = 0.04 m
x₁ = 0.32 - 0.30 = 0.02
[tex]W = \dfrac{1}{2}k(x_2^2-x_1^2)^2[/tex]
[tex]W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2[/tex]
W = 0.741 J
b) F = k x
25 = 1234.568 × x
x = 0.0205 m
x = 2.05 cm