percent yield = 50%
Explanation:
We have the following chemical reaction:
2 Na (s) + Br₂ (g)⟶ 2 NaBr (s)
number of moles = mass / molecular weight
number of moles of Na = 54.5 / 23 = 2.37 moles
number of moles of Br₂ = 61.3 / 160 = 0.38 moles
number of moles of NaBr = 61.3 / 103 = 0.6 moles (practical)
Talking into the account the stoichiometry in the chemical reaction we see that 2 moles of Na react with 1 mole of Br₂, so 2.37 moles of Na will react with 2.37 / 2 = 1.19 moles of Br₂ but we have only 0.38 moles of Br₂.
The limiting reactant will be Br₂.
Now we devise the following reasoning:
if 1 mole of Br₂ produce 2 moles of NaBr
then 0.38 moles of Br₂ produce X moles of NaBr
X = (0.38 × 2) / 1 = 0.76 moles of NaBr (theoretical)
yield = (practical quantity / theoretical quantity) × 100
yield = ( 0.38 / 0.76) × 100 = 50%
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yield of chemical reactions
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