You are studying the population growth of a species of fish. Assuming unlimited resources, no predators, and a constant per capita growth rate, if the population size in 2018 was 1100 and the population size in 2019 was 1500, what will the projected population size be in 2030? When inputting your answer, write a whole number (e.g., 1100, 1200, 1500) without decimals.

Although the information is not explicit enough, it will be assumed that a constant value will be determined to determine the increase in the fish population. Through an arithmetic progression, or numerical series, the constant number will be 400, that is, during each year the population increases by 400. Then, by 2030, there will be 5900.

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keshavgandhi04 keshavgandhi04 · Answer 2 · 2022-03-16T10:19:36+01:00

The population size of fish in 2030 will be 5900. it is calculated by using Arithmetic progression or number series.

What is arithmetic progression?

Arithmetic progression is a sequence of numbers such that the difference betwen two consecutive numbers will be a constant value.

In our example the growth rate is constant. The population increased by 400 in four years and it will remain constant.

By adding 400 in 1500 it will be 1900 in 2020 by continuing this process in 2030 population will be 5900.

Therefore the Population size in 2030 will be 5900.

Learn more about the Arithmetic progression here:

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