Answer:
6621.6 Joule
0.46525
Explanation:
F = Force = 356 N
s = Displacement = 18.6 m
m = Mass of block = 78 kg
Work done
[tex]W=F\times s\\\Rightarrow W=356\times 18.6\\\Rightarrow W=6621.6\ J[/tex]
The work done by the horizontal force is 6621.6 Joule
[tex]F=\mu mg\\\Rightarrow \mu=\frac{F}{mg}\\\Rightarrow \mu=\frac{356}{78\times 9.81}\\\Rightarrow \mu=0.46525[/tex]
The coefficient of friction between the block and the rough surface is 0.46525
