Answer:
4(x+x+1+x+2)=156, x=12
Step-by-step explanation:
let the numbers be x, x+1 and x+2.
Now,
4(x+x+1+x+2)=156
4(3x+3)=156
divide both side by 4
3x+3=156/4=39
subtract 3 from both sides
3x=39-3
3x=36
divide both sides by 3
x=36/3=12
x=12
Hence, the smallest of the integers is 12.