Respuesta :
Answer:
v₁ = - 0.65 m/s (opposite to the direction of Ramon)
Explanation:
Given that
m ₁= 93 kg (James )
m₂ = 55 kg ( Ramon)
v₂=1.1 m/s
The velocity of James = v₁
There is no any external force so linear momentum will remain conserve
0 = m ₁ v₁ + m₂ v₂
m ₁ v₁ = - m₂ v₂
93 v₁ = - 55 x 1.1
v₁ = - 0.65 m/s (opposite to the direction of Ramon)
Answer:
Velocity of james will be 0.6505 m/sec
Explanation:
We have given mass of James [tex]m_1=93 kg[/tex]
Mass of Ramon [tex]m_2=55 kg[/tex]
Velocity of Roman [tex]v_2=1.1m/sec[/tex]
Initial both are at rest so initial momentum = 0
From conservation of momentum we know that
Initial momentum = final momentum
So [tex]m_1v_1+m_2v_2=0[/tex]
[tex]93\times v_1+55\times 1.1=0[/tex]
[tex]v_1=-0.6505m/sec[/tex]
Negative sign shows the direction of velocity
