Answer:
F=507.7N
Explanation:
According to Newton's second law:
[tex]\sum F=m.a[/tex]
in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:
[tex]\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\[/tex]
there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.
[tex]F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N[/tex]