The acceleration of the car is [tex]1.4 m/s^2[/tex]
Explanation:
The motion of the car is a motion at constant acceleration, so we can use the following suvat equation
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the car in this problem, we have
u = 29 m/s
v = 24 m/s
s = 110 m
Solving the equation for a, we can find its acceleration:
[tex]a=\frac{v^2-u^2}{2s}=\frac{34^2-29^2}{2(110)}=1.4 m/s^2[/tex]
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