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in order to estimate the mean amount of time computer users spend on the internet each month.How many computer users must be surveyed in order to be 95% confident that your sample mean is within 10 minutes of the population mean?Assume that the standard deviation of the population of monthly time spent on the internet is 217 min.What is a major obstable to getting a good estimate of the population mean?Use technology to find the estimated minimum required sample size.



The minimum sample size required is ___ computer users.



What is a major obstacle to getting a good estimate of the population mean?

a) There may not be 1,809 computer users to survey
b) It is difficult to precisely measure the amount of time spent on the internet,invidating some data values
c) The data does not provide information on what the computers users did while on the internet
d) There are no obstacles to getting a good estimate of the population mean

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Answer:

The minimum sample size required is 1809 computer users.

Major obstacle to getting a good estimate of the population mean is

b) It is difficult to precisely measure the amount of time spent on the internet

Step-by-step explanation:

Minimum sample size can be found using the formula:

N≥[tex](\frac{z*s}{E})^2[/tex] where

  • N is the computer users surveyed
  • z is the corresponding z-score for 95% confidence level
  • s is the standard deviation of the population of monthly time spend on the internet
  • E is the expected margin of error from the mean.

Here z=1.96, s=217 min. E=10 min. If we put these values in the formula we get

N≥[tex](\frac{1.96*217}{10})^2[/tex] =1808.9≈ 1809

Major obstacle in the survey is that it is difficult to precisely measure the amount of time spent on the internet

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