So the final equation of line passing through (0, 2) and (4, 6) is:
[tex]y=x+2[/tex]
Further explanation:
Given points are:
(0,2) and (4,6)
We have to find the slope first
Let
(x1,y1) = (0,2)
(x2,y2)= (4,6)
Then
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{6-2}{4-0}\\=\frac{4}{4}\\=1[/tex]
The slope is m=1
The general form of lope-intercept form is:
[tex]y=mx+b\\Putting\ the\ value\ of\ slope\\y=(1)x+b\\y=x+b[/tex]
To find b we have to put one point in the equation
So, putting (0,2) in the equation
[tex]2=0+b\\b=2[/tex]
Putting the values of b and m in equation
[tex]y=x+2[/tex]
So the final equation of line passing through (0, 2) and (4, 6) is:
[tex]y=x+2[/tex]
Keywords: Slope of line, Point-intercept form
Learn more about derivation of equation of a line at:
- brainly.com/question/3126500
- brainly.com/question/2821386
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