Answer:
In both cases the Blackbody A will emit more radiation.
Explanation:
We have to remember that blackbodies that have different peacks but same surface area the one with the smallest peak will always emit more radiation, since the formula goes:
AT=B
Where A is peak and T is total temperature, and B is weins constant.
So if we solve it for A it would look like this:
A=B/T
Meaning that the higher the temperature the lowest the radiation.
