Answer:
To find the slope of this line, you would use the formula
y2 - y1/ x2 - x1
11 - 3 / 1 - (-1)=
8/2
4
The slope of your line would be 4
Step-by-step explanation:
Equation of line passing through (-1 , 3) and ( 1 , 11 ) is y - 3= 4x + 4
Solution:
Need to determine equation of line passing through points ( -1 , 3 ) and ( 1 ,11 ) Equation of line passing through point [tex]\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)[/tex] is given by
[tex]y-y_{1}=\frac{\left(y_{2}-y_{1}\right)}{\left(x_{2}-x_{1}\right)}\left(x-x_{1}\right)[/tex] ---- equation 1
[tex]\text { Here } x_{1}=-1, y_{1}=3, x_{2}=1, y_{2}=11[/tex]
Substituting given value in (1) we get
[tex]\begin{array}{l}{y-3=\frac{(11-3)}{(1-(-1))}(x-(-1))} \\\\ {=>y-3=\frac{8}{2}(x+1)} \\\\ {=>y-3=4(x+1)} \\\\ {=>y-3=4 x+4}\end{array}[/tex]
Hence equation of line passing through (-1 , 3) and ( 1 , 11 ) is y - 3 = 4x + 4
