Answer:
The maximum compression of the spring is 1.73 cm.
Explanation:
Given that,
Mass of box = 5.0 kg
Speed = 6.0 m/s
Spring constant = 60 N/cm
Suppose use the work-energy theorem to find the maximum compression of the spring.
We need to calculate the maximum compression of spring
Using work -energy theorem
[tex]\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2[/tex]
[tex]x^2=\dfrac{mv^2}{k}[/tex]
[tex]x=\sqrt{\dfrac{mv^2}{k}}[/tex]
Put the value into the formula
[tex]x=\sqrt{\dfrac{5.0\times(6.0)^2}{60}}[/tex]
[tex]x=1.73\ cm[/tex]
Hence, The maximum compression of the spring is 1.73 cm.
Answer:
Maximum compression distance of spring = 0.5 cm
Explanation:
Hooke's law of spring expansion states that the force exerted on the spring is proportional to the spring constant. In mathematical terms, this can be expressed as:
[tex]F = kE[/tex]
where F = Force on the spring
k = spring constant
E = length of stretch or compression.
but force = Ma
F = ma
= 5 * 6.0
= 30 N
Using Hooke's law
F = kE
30 = 60 E
E = 0.5 cm
So the spring is compressed by 0.5 cm
