Answer:
[tex]0.61 m/s^2[/tex]
Explanation:
The bike's acceleration can be found by using the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity of the bike
u is the initial velocity
a is the acceleration
s is the distance covered
For the bike in the problem,
u = 0
v = 7 m/s
d = 40 m
Solving the equation for a, we find the acceleration:
[tex]a=\frac{v^2-u^2}{2s}=\frac{7^2-0}{2(40)}=0.61 m/s^2[/tex]
