Answer:
12.5 m/s
Explanation:
The motion of the hammer is a free fall motion, so a uniformly accelerated motion, therefore we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
Where, taking downward as positive direction, we have:
s = 8 m is the displacement of the hammer
u = 0 is the initial velocity (it is dropped from rest)
v is the final velocity
[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity
Solving the equation for v, we find the final velocity:
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(8)}=12.5 m/s[/tex]
So, the final speed is 12.5 m/s.
